Physics

A gram molecule of a gas at 127°C expands isothermally until its volume is doubled. Find the amount of work done and heat absorbed.

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  1. The formula you will use for isothermic expansion is:

    Work(W) = 2.303 RT log(V2/V1)

    Let R = 8.3 J / mole-K (universal gas constant and V2/v1 = 2/1 = 2.

    Converting temperature to Kelvins:
    T = 127°C = 400K

    Work(W) = (2.3)(8.3)(400)log(2)

    W = 2.3 x 10^3 J

    To find the heat absorbed:

    2.3 x 10^3 J/4.2 = 548 cal.

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  2. One gram molecule of an ideal gas at 127°C expands isothermally until volume is doubled ,find the amount of work done given log=0.3010 R=8.31×10erg mol-¹°c

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