The equation below describes the motion of a particle (s = position in feet, t = time in seconds). Find the INSTANTANEOUS VELOCITY at each time given.
s = 1 / (t2 + 1) at time 2 seconds
I will assume you meant
s = 1/(t^2 + 1) , (use ^ to show exponentiation)
= (t^2 + 1)^-1
v = ds/dt = -1(t^2 + 1)^-2 (2t)
= -2t/(t^2 + 1)^2
so at t = 2
v = -4/(5)^2 = -4/25 ft/s
the negative tells me the object is slowing down