Maths plz help!

4x^2+8x-m=0,differs by 3 find the value of the constant m
plz help me??

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  1. differs from what by 3 ?
    do you mean the roots differ by 3 or something?

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  2. Yes the root

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  3. ok

    x = [ -8+/- sqrt (64-16m) ]/8
    so
    (1/8) * 2 * sqrt (64-16 m) = 3

    sqrt (64 - 16 m) = 12

    64 - 16 m = 144

    16 m = 80

    m = 5

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  4. If
    64-16m=144
    -16m=80
    m=-5? Can it be negative

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