Physics

A golfer rides in a golf cart at an average speed of 3.93 m/s for 43.3 s. She then gets out of the cart and starts walking at an average speed of 1.13 m/s. For how long (in seconds) must she walk if her average speed for the entire trip, riding and walking, is 1.99 m/s?

Can someone please help me? I don't understand how to do this.

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  1. take the definition of speed.
    average speed=total distance/total time

    avg speed=(distance1+distance2)/(time1+time2)

    now distance 1=3.93*43.3 meters, and time1=43.3sec

    you are looking for time 2
    distance2=1.13*time2

    solve for time2, a bit of algebra will be needed.

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    bobpursley

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