graph the function for the domain of 3x -y=1;D:(-3,-1,0,4)
3x - y = 1
y = 3x - 1
I assume those values after D: are the x values
for x=-3, y = 3(-3) - 1 = -10 ---> point (-3,-10)
for x = -1 , y = .....
carry on.
Now you have 4 points, so just plot them
Im confused
rrfvv
im confused
To graph the function 3x - y = 1 for the given domain D = (-3, -1, 0, 4), we need to find the corresponding values of y for each value of x in the domain.
First, let's rewrite the equation in the form y = mx + b, where m is the slope and b is the y-intercept.
3x - y = 1
To isolate y, we subtract 3x from both sides:
-y = -3x + 1
Now, multiply both sides by -1 to get y by itself:
y = 3x - 1
Now that we have the equation in slope-intercept form, we can easily find the values of y for each x-coordinate in the domain D.
For x = -3:
y = 3(-3) - 1
y = -9 - 1
y = -10
So, the first point on the graph is (-3, -10).
For x = -1:
y = 3(-1) - 1
y = -3 - 1
y = -4
The second point is (-1, -4).
For x = 0:
y = 3(0) - 1
y = 0 - 1
y = -1
The third point is (0, -1).
For x = 4:
y = 3(4) - 1
y = 12 - 1
y = 11
The fourth point is (4, 11).
Now, plot these four points on a graph and draw a straight line passing through them to represent the function:
Here's what the graph looks like:
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12 | *
| *
11 | *
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10 |
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9 |
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8 |
|
7 |
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6 |
|
5 |
|
4 | *
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3 |
|
2 |
|
1 | *
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0 - - - - - - - - - -
-3 -2 -1 0 1 2 3 4