I need help simplifing multiple exponents with integers. I.E (-2y^-3)^-3
(-2y^-3)^-3
is the same as:
(-2^-3) x (y^-3)^-3 which gives
(-1/8)(y^9)
To simplify (-2y^-3)^-3, you can follow these steps:
1. Start by understanding the order of operations. In this case, the exponent (-3) on the outside applies to the entire expression within the parentheses (-2y^-3).
2. Rewrite the expression by separating the base (-2) from the exponent (y^-3): (-2 * y^-3)^-3.
3. Next, simplify the base (-2) raised to the power of -3. To do this, you need to flip the fraction and change the sign of the exponent. So, (-2)^-3 becomes (-1/2)^3.
4. Now, focus on simplifying the exponent part (y^-3)^-3. Again, you need to flip the fraction and change the sign of the exponent, so (y^-3)^-3 becomes (1/y^3)^3.
5. Simplify further by cubing the fractional exponent (1/y^3)^3. This results in (1^3)/(y^3)^3, which simplifies to 1/y^9.
6. Finally, you can multiply the simplified base and the simplified exponent. Therefore, (-1/2)^3 multiplied by 1/y^9 equals -1/8y^9.
So, (-2y^-3)^-3 simplifies to -1/8y^9.