PART A)find x using the ratio of the sides 12 cm and 16 cm: x/20=12/16. Show your work
PART B) find x using the ratio of the sides 6 cm and 8 cm. Show your work
PART C) Explain why the answers to a and b should be the same
The triangles are
1st one x,12 cm, 6cm,
the 2nd one is 20 cm, 16 cm, 8 cm,
Big f, plz press f to pay respects.
a. Using the ratio of the sides 12 cm and 16 cm
x/20 = 12/16
x = (12(20)) / 16 = 15
b. Using the ratio of the sides 6 cm and 8 cm
x/20 = 6/8
x = (6(20)) / 8 = 15
c. The answer is the same since the ratio 12/16 and 6/8 is both equal to 3/4.
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Wow... this.. this is just sad. I feel bad for you help, may this question rest in piece.
so sad i came here 4 answers
BTW I hope you found you're answer @help! :P
PART A) To find the value of x using the given ratio of sides, we can set up a proportion:
x/20 = 12/16
First, we cross multiply:
16x = 12 * 20
Simplifying the right side:
16x = 240
Next, divide both sides by 16 to solve for x:
x = 240 / 16
Simplifying further:
x = 15 cm
Therefore, x is equal to 15 cm.
PART B) Similarly, for the second question, we set up a proportion using the given ratio of sides:
x/20 = 6/8
Cross multiply:
8x = 6 * 20
Simplify:
8x = 120
Now, divide both sides by 8:
x = 120 / 8
Further simplification:
x = 15 cm
So, x in this case is also equal to 15 cm.
PART C) The answers to parts A and B are both 15 cm. This is because in both cases, we are comparing the sides of two similar triangles. Similar triangles have corresponding angles that are equal and proportional sides.
In both questions, the ratios of the sides remain the same: 12/16 = 3/4 = 6/8. This means that the ratios of the corresponding sides in both triangles are equal. Therefore, we can conclude that the unknown side (x) must also be equal in both cases.
In other words, if we have two similar triangles with the same ratios of corresponding sides, the value of x will always be the same, regardless of the specific measurements of the sides.