Missing base

1/9= [. ] with exponent 2 please explain how I can get the answer thanks

1/3^2

What the missing base of 1/9 and the exponent is 2

To solve this problem, we need to find the missing base when the given fraction is raised to the power of 2.

Let's start by writing the given fraction and its exponent as an equation:
1/9 = x^2

To solve for the missing base, we can take the square root of both sides. This will undo the exponent of 2 and give us the missing base value:

√(1/9) = √(x^2)

On the left side, the square root of 1 is 1 and the square root of 9 is 3. So we have:

1/3 = x

Therefore, the missing base is 1/3.

To find the missing base of the expression 1/9 = [. ]^2, we need to take the square root of 1/9.

Here's how you can calculate it step by step:

1. Start with the equation: 1/9 = b^2. We need to solve for b, which is the missing base.

2. Take the square root of both sides of the equation to isolate the variable b. The square root cancels out the exponent of 2.

√(1/9) = √(b^2)

3. Simplify the equation:

The square root of 1/9 is calculated by taking the square root of the numerator and the square root of the denominator separately.

√1 / √9 = b

Simplifying further,

1/3 = b

Therefore, the missing base is 1/3.