a boy spent half of his money on sweet and one quarter on kolanut,if he has 6 naira left,how much does he have initially
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Let's assume the initial amount of money the boy had is "x" naira.
According to the given information, the boy spent half of his money on sweets. This means he spent (1/2)x naira on sweets.
He also spent one quarter of his money on kolanut, which is (1/4)x naira on kolanut.
So, the total amount of money spent is (1/2)x + (1/4)x = (3/4)x.
Given that the boy has 6 naira left, we can set up the equation:
x - (3/4)x = 6
Simplifying the equation:
(1/4)x = 6
Multiply both sides by 4 to get:
x = 24
Therefore, the boy initially had 24 naira.
To find out how much money the boy initially had, we can work backwards.
Let's assume the boy initially had "x" naira.
He spent half of his money on sweets, so he had x/2 naira remaining.
He also spent one quarter of his money on kolanut, so he had (x/2) - (x/4) = (2x - x)/4 = x/4 naira remaining.
Given that he has 6 naira left, we can set up the following equation:
(x/4) = 6
To solve for "x", we can multiply both sides of the equation by 4:
(x/4) * 4 = 6 * 4
x = 24
Therefore, the boy initially had 24 naira.