A rock is dropped from the top of a tall bridge after 3 seconds how far has the rock fallen due to gravity
a = 9.8 m/s^2
x = x0 + v0*t + (1/2)*a*t^2
x = 0 + 0 + (1/2)*(9.8m/s^2)*(3^2)
To calculate the distance the rock has fallen due to gravity, we can use the formula for free-fall motion:
distance = (1/2) * acceleration * time^2
In this case, we assume that the acceleration due to gravity is approximately -9.8 m/s^2 (negative because it is acting downward).
Given:
time = 3 seconds,
acceleration = -9.8 m/s^2
Substituting the values into the formula, we get:
distance = (1/2) * (-9.8 m/s^2) * (3 s)^2
= (1/2) * (-9.8 m/s^2) * 9 s^2
= -44.1 m
Therefore, after 3 seconds, the rock has fallen approximately 44.1 meters due to gravity.
To calculate the distance the rock has fallen due to gravity after 3 seconds, we can use the equation for free fall:
d = 0.5 * g * t^2
where:
d is the distance fallen,
g is the acceleration due to gravity (approximately 9.8 m/s^2),
t is the time in seconds.
Substituting the given values into the equation:
d = 0.5 * 9.8 * 3^2
d = 0.5 * 9.8 * 9
d = 4.9 * 9
d = 44.1 meters
Therefore, after 3 seconds, the rock would have fallen approximately 44.1 meters due to gravity.