in a single throw fair die what is probability that an odd number or perfect square greater then one show up
odds: 1, 3, 5
perfect squares greater than 1 : 4
so we have 1,3,4,5
and the prob is 4/6 = 2/3
I just realized I did this for you earlier.
Well, let's clown around with some probability math! To find the probability of rolling an odd number or a perfect square greater than one on a fair six-sided die, we need to count the favorable outcomes and divide by the total possible outcomes.
First, let's consider the odd numbers on a die: 1, 3, and 5. There are three odd numbers.
Then, let's think about the perfect squares greater than one: 4. There is only one perfect square greater than one.
Now, let's count the total possible outcomes on a fair die, which is six.
So, adding up the favorable outcomes, we have 3 + 1 = 4.
Therefore, the probability of rolling an odd number or a perfect square greater than one on a fair die is 4 out of 6, or simplifying it, 2 out of 3. In decimal form, that's approximately 0.6667, or about 66.67%.
Remember, though, that in the world of probability, nothing is guaranteed. So, even if there's a 66.67% chance, I suppose it's still possible for that die to be stubborn and roll something less thrilling. Happy rolling!
To find the probability of an odd number or a perfect square greater than one showing up on a fair die, we need to determine the total number of favorable outcomes and the total number of possible outcomes.
First, let's determine the number of favorable outcomes:
1. Odd Numbers: The odd numbers on a die are 1, 3, and 5.
2. Perfect Squares Greater than One: The perfect squares greater than one on a die are 4 and 9.
Thus, there are 5 favorable outcomes: 1, 3, 4, 5, and 6.
Next, let's determine the total number of possible outcomes:
On a fair die, there are 6 possible outcomes: 1, 2, 3, 4, 5, and 6.
Therefore, the probability of an odd number or a perfect square greater than one showing up on a fair die is:
Probability = (Number of Favorable Outcomes) / (Number of Possible Outcomes)
Probability = 5 / 6 ≈ 0.8333 or 83.33%
So, the probability is approximately 0.8333 or 83.33%.
To find the probability of an event, we need to know the number of favorable outcomes (the outcomes we are interested in) and the total number of possible outcomes.
In this case, we are interested in two events: the event of rolling an odd number and the event of rolling a perfect square greater than one.
1. Odd numbers: In a fair die, there are three odd numbers, which are 1, 3, and 5.
2. Perfect squares greater than one: The perfect squares greater than one that can show up on a fair die are 4 and 9.
Now, let's calculate the total number of possible outcomes. On a fair die, there are six sides, numbered from 1 to 6.
So, the total number of possible outcomes is 6.
To find the probability, we add the number of favorable outcomes and divide it by the total number of possible outcomes:
Number of favorable outcomes = 3 (odd numbers) + 2 (perfect squares) = 5
Probability = Number of favorable outcomes / Total number of possible outcomes
= 5 / 6
Therefore, the probability of rolling an odd number or a perfect square greater than one on a fair die is 5/6 or approximately 0.8333.