what is the percent by mass of solution (d =1,3g/ml) of urea ((NH2)2CO) with molarity 8,4mol/l?

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  1. % w/w = (grams solute/g solution)*100 = ?.

    M = 8.4 mols/L.
    mols = grams/molar mass so g = mols x molar mass = 8.4 x 62 = approx 521 g in the solution so g solute = approx 521.
    The solution has a mass of 1.3g x 1000 = approx 1300 grams.

    Now % = approx 521/1300)*100 = ?

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