Jake needs to catch 1 10 pound fish to last 5 days. He catches 2 3.33 pound fish, 1 2.11 pound, and 1 1 pound fish. How long will he survive with that amount of food?
He eats 2 lb/day.
time to last=lbs/rate=(6,66+2.11+1)/2 days
Total = 23*33 + 12*11 + 1*1 = 892 Lbs.
892Lbs * 5days/10Lbs = 446 Days.
Oops! I misread the numbers.
Total=2*3.33 + 1*2.11 + 1*1 = 9.77 Lbs.
9.77Lbs * 5days/10Lbs. = 4.9 Days or 5
days.
To determine how long Jake will survive with the given amount of food, we need to calculate the total weight of the fish he has caught. Then, we divide that weight by the weight he needs to last for 5 days.
First, let's calculate the total weight of the fish Jake has caught:
2 (fish of 3.33 pounds each) + 1 (fish of 2.11 pounds) + 1 (fish of 1 pound)
So, the total weight of the fish Jake has caught is:
2 * 3.33 + 2.11 + 1 = 8.77 pounds
Next, we divide the total weight of the fish by the amount of fish Jake needs to last for 5 days:
8.77 pounds รท 10 pounds = 0.877
This tells us that Jake only has enough food to last for 0.877 of 5 days.
To determine the number of days Jake can survive with the given amount of food, we multiply 0.877 by 5:
0.877 * 5 = 4.385
Therefore, Jake will be able to survive for approximately 4.385 days with the amount of food he has caught.