Write the equation of a line that is perpendicular to the given line and that passes through the given point.
Y-3=8/3(x+2);(-2,3)
I have no clue :,(
slope of given line = 8/3
so slope of perendicular line = -3/8
equation :
y-3 = (-3/8)(x+2)
Y-3=8/3(x+2);(-2,3)
I have no clue :,(
so slope of perendicular line = -3/8
equation :
y-3 = (-3/8)(x+2)