A body whose weight is W1=75N is tied to another body whose weight is W2=45N .If the coefficient of kinetic friction between W1 and the inclined plane (25°)AB is 0.15,calculate the coefficient of kinetic between W2 and the inclined plane(15°) BC when the two masses slide down at constant velocity. (answer 0.23)

Question

A body whose weight is W1=75N is tied to another body whose weight is W2=45N .If the coefficient of kinetic friction between W1 and the inclined plane (25°)AB is 0.15,calculate the coefficient of kinetic between W2 and the inclined plane(15°) BC when the two masses slide down at constant velocity. (answer 0.23)

Answer 1

W1 and W2 are connected by a rope that is passed through apulley.

Answer 2

please its urgent

Answer 3

To find the coefficient of kinetic friction between W2 and the inclined plane BC, we can use the same method as finding the coefficient of kinetic friction between W1 and the inclined plane AB.

Let's break down the steps to get the answer:

Step 1: Draw a diagram
Draw a diagram of the situation described in the problem. Label all the given information.

Step 2: Determine the forces
Identify all the forces acting on each body. For W1 on the inclined plane AB, there are three forces: the weight (W1), the normal force (N1), and the force of friction (f1). For W2 on the inclined plane BC, the forces are the weight (W2), the normal force (N2), and the force of friction (f2).

Step 3: Resolve forces
Resolve the forces into components parallel and perpendicular to the inclined planes. The parallel component of the weight will drive the sliding motion of the bodies, and the perpendicular component of the weight will provide the normal force.

For the inclined plane AB:
W1_parallel = W1 * sin(25°)
W1_perpendicular = W1 * cos(25°)

For the inclined plane BC:
W2_parallel = W2 * sin(15°)
W2_perpendicular = W2 * cos(15°)

Step 4: Apply Newton's second law
Since the bodies are sliding down the inclined planes at constant velocity, the net force acting on each body is zero. Therefore, we can write the equation:

For W1 on the inclined plane AB:
f1 - W1_parallel = 0
f1 = W1_parallel

For W2 on the inclined plane BC:
f2 - W2_parallel = 0
f2 = W2_parallel

Step 5: Calculate the coefficient of kinetic friction
The coefficient of kinetic friction is the ratio of the force of friction to the normal force.

For W1 on the inclined plane AB:
μ1 = f1 / N1 = f1 / (W1_perpendicular)

For W2 on the inclined plane BC:
μ2 = f2 / N2 = f2 / (W2_perpendicular)

Step 6: Substitute values and calculate
Substitute the given values and the resolved forces into the calculations for μ1 and μ2:

For W1 on the inclined plane AB:
μ1 = (W1 * sin(25°)) / (W1 * cos(25°)) = tan(25°) = 0.4663

For W2 on the inclined plane BC:
μ2 = (W2 * sin(15°)) / (W2 * cos(15°)) = tan(15°) = 0.2679

Therefore, the coefficient of kinetic friction between W2 and the inclined plane BC is approximately 0.2679. This does not match the given answer of 0.23, so please double-check the values or calculations provided in the problem statement.