if three resistors are connected in parallel there are 10 ohm 20 ohm and 60 ohm to a battery of 12 volt then find the effective resistance ?
just use the formula:
1/R = 1/10 + 1/20 + 1/60
The voltage does not matter. The formula works because each resistor allows a current to pass, and the currents add up to the total.
Since E=IR, I=E/R, and you have a total current of
12/10 + 12/20 + 12/60
That current is the total current I, and R=12/I. That is, I=12/R, the total resistance.
To find the effective resistance of three resistors connected in parallel, you can use the following formula:
1/Reff = 1/R1 + 1/R2 + 1/R3
Where Reff is the effective resistance and R1, R2, and R3 are the resistances of the individual resistors.
Let's substitute the given values:
1/Reff = 1/10 + 1/20 + 1/60
To simplify the equation, let's find the common denominator:
1/Reff = 6/60 + 3/60 + 1/60
Now we can add the fractions together:
1/Reff = (6 + 3 + 1) / 60
1/Reff = 10 / 60
To isolate Reff, we can take the reciprocal of both sides:
Reff = 60 / 10
Reff = 6 ohms
Therefore, the effective resistance of the three resistors connected in parallel is 6 ohms.