pobability

Suppose that 16% of the CD's that are distributed are defective. If you choose 5 CD's randomly, what is the probability that at least 1 of them is defective?

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  1. prob(defect) = .16
    prob(not defect) = .84

    prob(at least 1 defective)
    = 1 - prob(none defective)
    = 1 - C(5,0) (.16)^0 (.84)^5
    = 1 - .84^5
    = appr.582

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  2. 90

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