MATH

Reiny - the problem with the different inequality signs was typed from the textbook. I will notify instructor Thanks

Another problem
3<5x-27<53
1st part
3<5x-27
27+3<5x-27+27
30/5 < 5x/5
6<x

2nd part
5x-27<53
5x-27+27<53+27
5x/5 < 80/5
x<16

combine 6<x<16

Am I correct?

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  1. you can do both at once

    3 < 5x-27 < 53
    30 < 5x < 80
    6 < x < 16

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  2. the nice thing about having the orientation of the inequality signs going the same way is that you can just perform the solution as it stands

    3<5x-27<53
    you are trying to get just "x" in the middle, so
    add 27 to all parts

    30 < 5x < 80
    divide by +5

    6 < x < 16 , same as yours

    Now wasn't that easy, just took 2 steps.
    That is why the orientation of the signs going the same way is so important.

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  3. Thanks

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