Can anyone explain simply how Surds work and a simple process how to solve them.
Also a simple explanation for factorisation is needed.
You have to be much more specific. Surds is a very encompassing term.
Since this is not my area of expertise, I searched Google under the key words "surds" to get these possible sources:
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http://www.mathsisfun.com/surds.html
http://en.wikipedia.org/wiki/Nth_root
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I hope this helps. Thanks for asking.
the question says " write an irrational fraction that when rationalised the solution is 5. prove"
please help
suck me
I have got aproject in maths regarding surds . i want theory of surds
25
Sure, I can explain surds and also provide you with a simple process to solve them.
In mathematics, surds are irrational numbers that are expressed as the square root of a number that is not a perfect square. An irrational number is a number that cannot be expressed as a fraction or a decimal that terminates or repeats.
To solve surds, follow these steps:
1. Simplify the surd: If the surd can be simplified by taking out a perfect square from the radicand (the number inside the square root), do so. For example, if you have √18, you can simplify it as √9 * √2 = 3√2.
2. Rationalize the denominator: If the surd is in the denominator of a fraction, you may want to rationalize it by multiplying the numerator and denominator by the conjugate of the surd. For example, if you have 1/√2, you can rationalize it as 1/√2 * √2/√2 = √2/2.
Now, let's move on to factorization.
Factorization is breaking down a number or an algebraic expression into its factors, which are the numbers or expressions that multiply together to give the original number or expression. The factors can be either numbers or other algebraic expressions.
To factorize a number, you can follow these steps:
1. Find the prime factors: Start by dividing the number by the smallest prime number possible and continue until you can no longer divide evenly. For example, to factorize 24, divide it by 2 to get 12, then divide 12 by 2 to get 6, and finally divide 6 by 2 to get 3. So the prime factors of 24 are 2, 2, 2, and 3.
2. Write the prime factors as a product: Once you have found the prime factors, you can write the original number as a product of its prime factors. In the case of 24, you can express it as 2 * 2 * 2 * 3.
Factorization of algebraic expressions can be a bit more complex, but the basic idea is to look for common factors and use algebraic techniques such as factoring by grouping or recognizing special factorization patterns (e.g., the difference of squares).
I hope this explanation helps you with your math project! If you have any further questions, feel free to ask.