My question is: What is the mass of solute in a 25.0 g of 10.0 %(m/v) sucrose solution? (Assume density of solution is 1.15 g/mL)
I was wondering if my answer: 2.17 g solute is correct?
Thank you
To calculate the mass of solute in a solution, you will need to use the given concentration 10.0% (m/v) and the volume of the solution.
First, convert the given percentage to a decimal by dividing it by 100: 10.0% = 0.10.
Next, use the definition of percent concentration:
Percent (m/v) = (mass of solute / volume of solution) * 100
Since you are given the volume of the solution (25.0 g) and the density of the solution (1.15 g/mL), you can calculate the volume of the solution.
Volume of solution = mass of solution / density
Volume of solution = 25.0 g / 1.15 g/mL
Volume of solution = 21.74 mL
Now you have the volume of the solution, so you can rearrange the equation to solve for the mass of the solute:
Mass of solute = (percent m/v * volume of solution) / 100
Mass of solute = (0.10 * 21.74 mL) / 100
Mass of solute = 2.174 g (rounded to three decimal places)
Therefore, the correct answer for the mass of the solute in a 25.0 g of 10.0% (m/v) sucrose solution is 2.174 g, not 2.17 g.