CALCULATE THE FORMULA UNITS IN 285G OF IRON (111)PHOSPHATE?
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To calculate the formula units in 285g of iron (III) phosphate (FePO4), we need to follow these steps:
Step 1: Determine the molar mass of FePO4.
The molar mass is the sum of the atomic masses of each element in the compound. We can find the atomic masses from the periodic table.
Fe (Iron) = 55.85 g/mol
P (Phosphorus) = 30.97 g/mol
O (Oxygen) = 16.00 g/mol (there are 4 oxygen atoms in FePO4)
Molar mass of FePO4 = (55.85 g/mol) + (30.97 g/mol) + (4 * 16.00 g/mol)
= 150.85 g/mol
Step 2: Calculate the number of moles in 285g of FePO4.
The number of moles can be determined using the formula:
Moles = Mass (g) / Molar mass (g/mol)
Moles of FePO4 = 285g / 150.85 g/mol
≈ 1.887 moles
Step 3: Calculate the number of formula units.
The number of formula units can be found by multiplying the number of moles by Avogadro's number (6.022 x 10^23 formula units/mol).
Number of formula units = Moles x Avogadro's number
= 1.887 moles x 6.022 x 10^23 formula units/mol
≈ 1.136 x 10^24 formula units
Therefore, there are approximately 1.136 x 10^24 formula units in 285g of iron (III) phosphate.
To calculate the formula units in 285g of Iron (III) Phosphate, you need to follow a series of steps:
Step 1: Determine the molar mass of Iron (III) Phosphate.
- The molar mass of Iron (III) Phosphate (FePO4) can be calculated by adding the atomic masses of each element present in the compound.
- The atomic mass of Iron (Fe) is 55.845 g/mol.
- The atomic mass of Phosphorus (P) is 30.974 g/mol.
- The atomic mass of Oxygen (O) is 15.999 g/mol (there are four oxygen atoms in the compound).
- So, the molar mass of Iron (III) Phosphate can be calculated as follows:
Molar Mass = (55.845 g/mol) + (30.974 g/mol) + 4 x (15.999 g/mol)
Step 2: Calculate the number of moles of Iron (III) Phosphate.
- To calculate the moles, divide the given mass by the molar mass.
- Moles of Iron (III) Phosphate = Mass of Iron (III) Phosphate / Molar Mass of Iron (III) Phosphate
- Substituting the given values:
Moles of Iron (III) Phosphate = 285 g / Molar Mass of Iron (III) Phosphate
Step 3: Calculate the formula units.
- The formula units represent the number of formula units in one mole of a compound. It is equal to Avogadro's number (6.02 x 10^23) since one mole of any substance contains that many particles.
- To calculate formula units, multiply the moles of Iron (III) Phosphate by Avogadro's number.
- Formula Units of Iron (III) Phosphate = Moles of Iron (III) Phosphate x Avogadro's number
By following these steps, you can now calculate the formula units in 285g of Iron (III) Phosphate.
1. Find the formula mass of FePO4
2. Divide the mass of FePO4 (285g) by the formula mass. That will give you the number of formula units or moles of FePO4