A team of dogs drags a 81.2 kg sled 3.12 km over a horizontal surface at a constant speed.The coefficient of friction between the sled and the snow is 0.172.

The acceleration of gravity is 9.8 m/s^2
Find the work done by the dogs.
Answer in units of kJ.

That is wrong

yah its wrong smh

Well, let's not underestimate these hardworking doggos! To find the work done by the dogs, we need to calculate the force of friction first.

The formula to calculate the force of friction is:

Force of Friction = coefficient of friction * Normal force

The normal force is equal to the weight of the sled, which is the mass multiplied by the acceleration due to gravity:

Normal force = mass * acceleration due to gravity

Now let's plug in the values:

Normal force = 81.2 kg * 9.8 m/s^2
Normal force ≈ 796.96 N

Using the formula for work:

Work = force * displacement * cos(theta)

Since the sled and the force of friction are in opposite directions (180 degrees), the cosine of theta is -1.

Work = - force of friction * displacement

Now let's calculate the work done:

Work = - ( coefficient of friction * Normal force ) * displacement
Work = - (0.172 * 796.96 N) * 3.12 km

Converting kilometers to meters (1 km = 1000 m):

Work = - (0.172 * 796.96 N) * (3.12 km * 1000 m/km)
Work ≈ - 416.65 * 3120 m²

Now, let's convert the work into kilojoules:

Work ≈ - 1299655.2 J

Dividing by 1000 to convert joules to kilojoules:

Work ≈ -1299.655 kJ

So, the work done by the dogs, using humorously negative terminology, is approximately -1299.655 kJ. Keep up the pawsome work, dogs!

To find the work done by the dogs, we can use the formula:

Work = force × distance × cos(θ)

Where:
- Work is the work done by the dogs
- force is the force of friction between the sled and the snow
- distance is the distance the sled is dragged
- θ is the angle between the force of friction and the direction of motion

In this case, the sled is being dragged horizontally, so the angle between the force of friction and the direction of motion is 0°. Therefore, cos(θ) = cos(0°) = 1.

The force of friction can be calculated using the formula:

force of friction = coefficient of friction × normal force

The normal force is equal to the weight of the sled since it is on a horizontal surface. The weight of the sled can be calculated using the formula:

weight = mass × acceleration due to gravity

Substituting the given values, we have:
mass = 81.2 kg
acceleration due to gravity = 9.8 m/s^2

So, weight = 81.2 kg × 9.8 m/s^2

Now we can calculate the force of friction:
force of friction = 0.172 × weight

Next, we can substitute the values in the formula for work:
Work = force of friction × distance × cos(θ)
= (0.172 × weight) × 3.12 km × cos(0°)

Note: We need to convert the distance from kilometers to meters, and the answer should be in kilojoules (kJ).

Converting 3.12 km to meters:
3.12 km = 3.12 × 1000 m = 3120 m

Substituting the values, we have:
Work = (0.172 × weight) × 3120 m × cos(0°)

Now, let's calculate the weight:
weight = 81.2 kg × 9.8 m/s^2

Substituting the value of weight, we have:
Work = (0.172 × 81.2 kg × 9.8 m/s^2) × 3120 m × cos(0°)

Calculating the expression inside the parentheses and the cos(0°), we can find the final answer in kilojoules.

Ws = M*g = 81.2 * 9.8 = 796 N. = Wt. of

sled = Normal force, Fn.

Fk = u*Fn = 0.172 * 796 = 137 N. = Force of kinetic friction.

Fap-Fk = M*a.
Fap-137 = M*0 = 0.
Fap = 137 N. = Force applied.

Work = Fap*d = 137 * 3.12 = 427 J. = 0.427 kJ.