A team of dogs drags a 81.2 kg sled 3.12 km over a horizontal surface at a constant speed.The coefficient of friction between the sled and the snow is 0.172.
The acceleration of gravity is 9.8 m/s^2
Find the work done by the dogs.
Answer in units of kJ.

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  1. Ws = M*g = 81.2 * 9.8 = 796 N. = Wt. of
    sled = Normal force, Fn.

    Fk = u*Fn = 0.172 * 796 = 137 N. = Force of kinetic friction.

    Fap-Fk = M*a.
    Fap-137 = M*0 = 0.
    Fap = 137 N. = Force applied.

    Work = Fap*d = 137 * 3.12 = 427 J. = 0.427 kJ.

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  2. That is wrong

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