I don't remember how to solve this.

The question is: For what values of a is the expression 7(x-2)5 negative? Write answer using interval notation.

I assume you meant

7(x-2)^5 < 0
so (x-2)^5 < 0

we know (any negative)^5 < 0
so x-2 < 0
or
x < 2

oops sorry. it's actually

For what values of a is the expression 7(x-2)-5 negative?

That's even easier

7(x-2) - 5 < 0
7x - 14 - 5 < 0
7x < 19
x <19/7

Ok so I did it correctly. Thank you

To solve this question, you need to find the values of "a" that make the expression 7(x-2)5 negative. Here's how you can do it:

1. Start by simplifying the expression: 7(x-2)5 = 35(x-2)
2. We know that a product is negative when one of the factors is negative and the other is positive. In this case, the factor 35 is positive, so we need to find the values of "x-2" that make the expression negative.
3. Set x-2 < 0 and solve for x:
x-2 < 0
x < 2

Now that we have found the values of "x" that make the expression negative, we can express the answer using interval notation.

The answer is: (-∞, 2)