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Chemistry. I got the wrong answer. Plz help

A sample of sodium reacts completely with 142 g of chlorine, forming 234 g of sodium chloride. What mass of sodium reacted?

I took 142g of Cl / 35.5g/mol = 4 mols of Cl

Then I took 58.44g/mol x 4 mols of Cl = 233.76

It asked for three significant figures only so I put 233 and 234 but i got the worng answer twice.

Somebody plz help!

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Dominick

  1. Write out your balanced equation for the reaction first.

    2Na + Cl2 --> 2NaCl
    ? 142g 234g

    Mols of Cl2
    142g / 71 g/mole
    = 2 mol of Cl2

    Because of the balanced equation, one mol of Cl2 requires 2 mols of Na for all of the chlorine to be used up
    ... 4 mol of Na

    4 mol * 23 g/mol
    = 92 g of Na

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    R

  2. The other way to do this...

    234g sodium chloride - 142g of chlorine = 92g of sodium

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    Anonymous

  4. NaCl = 23+35.5 = 58.5 g/mol
    so 234/58.5 = 4 mols of NaCl

    that requires
    23 * 4 = 93 grams of Na

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    Damon

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