Abigail is 15, and Cynthia is 27. How many years ago was Abigail twice as young as Cynthia?
Abigail is 15, and Cynthia is 27. How many years ago was Abigail twice as young as Cynthia?
12
24
To find out how many years ago Abigail was twice as young as Cynthia, we need to set up an equation using algebra.
Let's assume that x represents the number of years ago we are looking for.
At that time, Abigail's age would be 15 - x, and Cynthia's age would be 27 - x.
According to the problem, Abigail was twice as young as Cynthia, so we can write the equation:
15 - x = 2(27 - x)
Now we can solve this equation by simplifying and isolating the variable x.
15 - x = 54 - 2x
We can move the x terms to one side of the equation:
2x - x = 54 - 15
This simplifies to:
x = 39
Therefore, 39 years ago, Abigail was twice as young as Cynthia.
Abigail is 15, and Cynthia is 27. How many years ago was Abigail twice as young as Cynthia?
14, 26
13, 25
12, 24
11, 23
10, 22
Which of those pairs of number meets the criterion?