A sample consist only NaCl and NaBr has amass of 0.7648gm.
This sample is place in solution in which excess of silver is added which forma precipitate the AgCl and AgBr has amass of 1.5758 gm .
what's the percentage of Cl and Br in original sample ?
To find the percentage of Cl and Br in the original sample, we can use the law of conservation of mass.
First, let's calculate the mass of AgCl and AgBr formed in the reaction.
The mass of AgCl formed can be found using the following equation:
Mass of AgCl = Mass of sample - Mass after reaction
= 0.7648 gm - 1.5758 gm
= -0.811 gm
Note: The negative value indicates an error or miscalculation. The mass after the reaction should never be greater than the mass of the sample.
Likewise, the mass of AgBr can be found using the same method:
Mass of AgBr = Mass of sample - Mass after reaction
= 0.7648 gm - 1.5758 gm
= -0.811 gm
Again, the negative value indicates an error or miscalculation. The correct mass should be positive.
Given the negative values obtained for the mass of AgCl and AgBr, it seems there was an error in the calculations or the experimental data.
To calculate the percentage of Cl and Br accurately, we need the correct mass values of AgCl and AgBr formed in the reaction. Once we have the correct masses of AgCl and AgBr, we can use the following formulas to find the percentages:
Percentage of Cl = (Mass of AgCl / Mass of sample) * 100
Percentage of Br = (Mass of AgBr / Mass of sample) * 100
Unfortunately, without the correct masses of AgCl and AgBr, we cannot accurately determine the percentages of Cl and Br in the original sample.