Mary is 3 times as old as her son.In 12 years,Mary's age will be one less than twice her son's age.Find their ages now.
12
Sons age now-12
Moms age-36
To solve this problem, let's set up equations based on the given information.
Let's assume Mary's age is M and her son's age is S.
1. "Mary is 3 times as old as her son" means M = 3S.
2. "In 12 years, Mary's age will be one less than twice her son's age" means (M + 12) = 2(S + 12) - 1.
Now, we have a system of two equations. We can substitute the value of M from equation 1 into equation 2 to solve for S.
M = 3S
(M + 12) = 2(S + 12) - 1
Substituting M = 3S into equation 2:
(3S + 12) = 2(S + 12) - 1
3S + 12 = 2S + 24 - 1
3S + 12 = 2S + 23
3S - 2S = 23 - 12
S = 11
Now that we know S = 11, we can substitute this value back into equation 1 to find M:
M = 3S
M = 3 * 11
M = 33
Therefore, Mary's present age is 33 and her son's present age is 11.
let the age of son be X
Mary 3X
3X+12=2X-1
solve for X