34.09 ml of 0.251 M KOH is required to tritate a 10.2951 g sample of acetic acid solution. The density of the solution had been previously found to be 1.007g/ml. what is the molarity of the aetic acid solution?.
MolarityAcid*VolumeAcid=MolarityBase*Volumebase
MolarityAcit=.251* 34,08/volumeacid
but volume acid=massacid/density
And, there you have it.
molarityAcit=.251* 34.08/(10.2951/1.007)