sum of Rs.7700 is to be dividedamong three brothers Zain, Zaid and Zoaib in such a way that simple intereston each part at 5% per annum after 1,2 and 3 years, respectively remains equal. The share of Zain is more than that of Zoaib by?
let the parts be
x, y, and 7700-x-y
interest on x for 1 year = 1(.05)x
interest on y for 2 years = 2(.05)y = .1y
interest on 7700-x-y = 3(.05)(7700 - x - y)
as I read the question, these are all the same
.05x = .1y
x = 2y
.05x = .15(7700-x-xy)
x = 3(7700 - x - y)
x = 23100 - 3x - 3y
subbing in x = 2y
2y = 23100 - 6y - 3y
11y = 23100
y = 2100
then x = 2y = 4200
the third part = 7700-2100-4200 = 1400
carry on
it is right
4200-1400=2800 which is answer
Its wrong dear
yeah its wrong
Well, dividing money among brothers can be a tricky business. But don't worry, I'm here to help you figure it out and add some humor to the equation!
Let's assume that Zain gets x Rs., Zaid gets y Rs., and Zoaib gets z Rs. Now, according to the given conditions, the simple interest on each part after 1, 2, and 3 years remains equal.
So, let's do some math and have some fun!
Now, we know that Simple Interest (SI) can be calculated using the formula SI = (Principal x Rate x Time)/100.
For Zain's share after 1 year, the SI is (x * 5 * 1) / 100.
For Zaid's share after 2 years, the SI is (y * 5 * 2) / 100.
And for Zoaib's share after 3 years, the SI is (z * 5 * 3) / 100.
Since the SI needs to remain equal, we can set up an equation:
(x * 5 * 1) / 100 = (y * 5 * 2) / 100 = (z * 5 * 3) / 100
Simplifying it further, we get:
x / 20 = y / 10 = z / 6
Now, we need to find the share of Zain compared to Zoaib. So, let's compare their shares:
x / z = (20 * z) / (6 * z)
x / z = 20 / 6
x / z = 10 / 3
Now, let's multiply both sides by 3 to get rid of the fraction:
3 * (x / z) = (10 / 3) * 3
x / z = 10
So, the share of Zain is 10 times the share of Zoaib. In other words, Zain's share is more than Zoaib's share by 10 times.
I hope that brings a smile to your face while doing the calculations. Remember, laughter is the best interest in life!
To find out the share of Zain and the difference between Zain's and Zoaib's share, we can start by assuming the share of Zain as x.
Since Zain's share is more than Zoaib's share by a certain amount, we can consider Zoaib's share as x - y (where y is the difference between their shares).
According to the given information, the simple interest on each part after 1, 2, and 3 years should be equal.
Let's calculate the simple interest for each brother's share:
For Zain's share (x):
Simple Interest after 1 year = x * 5/100
Simple Interest after 2 years = x * 2 * 5/100
Simple Interest after 3 years = x * 3 * 5/100
For Zoaib's share (x - y):
Simple Interest after 1 year = (x - y) * 5/100
Simple Interest after 2 years = (x - y) * 2 * 5/100
Simple Interest after 3 years = (x - y) * 3 * 5/100
According to the problem, these interests should be equal. So we can set up the following equation:
x * 5/100 = (x - y) * 5/100
2 * x * 5/100 = 2 * (x - y) * 5/100
3 * x * 5/100 = 3 * (x - y) * 5/100
Now, let's solve these equations step by step:
0.05x = 0.05(x - y)
0.1x = 0.1(x - y)
0.15x = 0.15(x - y)
Cancel out the denominator:
x = x - y
2x = 2(x - y)
3x = 3(x - y)
Now, let's simplify these equations:
x = x - y (no change)
2x = 2x - 2y (expand)
3x = 3x - 3y (expand)
Rearranging the equation:
x - x = -y
2x - 2x = -2y
3x - 3x = -3y
Simplifying further, we have:
0 = -y
0 = -2y
0 = -3y
Since y is equal to 0 in each equation, it means there is no difference between Zain's and Zoaib's shares. Thus, the share of Zain is not more than that of Zoaib by any amount (the difference is zero in this case).