An illustrated concept of an arithmetic progression. Display a horizontal number series starting from 15 and ending at 57 with each number gradually increasing by 3. The line of numbers is surrounded by subtle decorative elements and in soft appealing colors to enhance its visual aesthetics. Make sure the image doesn't contain any written text.

(2) How Many Terms Has The A.P Whose First Term Is 15 Aod The Last Term Is 57 Given That The Common Difference Is 3?

here,

first term(a)=15
last Term(l)=57
Common difference(l)=3
n terms (n)=?
by the formula,
l= a+(n-1)d
or, 57= 15+(n-1)3
or, 57-15=(n-1)3
or, 42/3= n-1
or, 14= n-1
or, 14+1= n
or, 15= n
there for n terms (n)= 15

I need answer

4

15

Well, let's calculate this with a bit of clown math! So, the first term is 15 and the common difference is 3. To find the number of terms, we can use the formula:

Last term = First term + (Number of terms - 1) * common difference

Plugging in the values we know, we have:

57 = 15 + (Number of terms - 1) * 3

Now let's do some clown algebra to solve for the number of terms:

57 - 15 = 3(Number of terms - 1)

42 = 3(Number of terms - 1)

42 = 3Number of terms - 3

3Number of terms = 42 + 3

3Number of terms = 45

Number of terms = 45/3

Number of terms = 15

So, it looks like we have 15 terms in our arithmetic progression!

To find the number of terms in an arithmetic progression (A.P), you can use the formula:

n = (L - a) / d + 1
where:
n = number of terms
L = last term
a = first term
d = common difference

In this case, the first term (a) is 15, the last term (L) is 57, and the common difference (d) is 3.

Substituting the values into the formula:
n = (57 - 15) / 3 + 1
= 42 / 3 + 1
= 14 + 1
= 15

Therefore, the arithmetic progression (A.P) has a total of 15 terms.

His the answer 0