Find the magnitude acceleration of a jeep that is initially moving at 18m/s and comes to a complete stop in 4.2s
a = Δv/Δt = (-18m/s) / (4.2s) = -4.86 m/s^2
I'm sorry. We have no tutors here that are qualified in the School Subject "y".
4.3
To find the magnitude of acceleration, we can use the equation:
acceleration = (final velocity - initial velocity) / time
Here, the initial velocity is 18 m/s, the final velocity is 0 m/s (since the jeep comes to a complete stop), and the time is 4.2 s.
Plugging in these values into the equation, we get:
acceleration = (0 m/s - 18 m/s) / 4.2 s
Simplifying the expression:
acceleration = -18 m/s / 4.2 s
Finally, calculating the value:
acceleration = -4.286 m/s²
Therefore, the magnitude of acceleration for the jeep is 4.286 m/s².