College Algebra

Find the equation of the line passing thrugh the centers of the circles defined by x^2+y^2-6x+14y+46=0 and 3(x-2)^2+3y^2=6

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  1. circle defined by
    x^2+y^2-6x+14y+46=0

    x2 - 6x + 9 + y^2 + 14x + 49 = -46 + 9 + 49
    (x-3)^2 + (y+7)^2 = 12
    centre is (3,-7)

    the centre of the other circle is (2,0)

    can you find the equation of a straight line passing through (3,-7) and (2.0) ?

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  2. (x-2)^2+(y+3)^2=0

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