How many grams of cesium chloride (CsCl) will be needed to make 750. mL of a 0.100 M CsCl aqueous solution? The formula mass of CsCl is 168.36 g/mol
Molarity: M = (mol solute) / (L of solution)
To find the mass of cesium chloride needed, we can use the following steps:
Step 1: Convert the given volume of the solution from milliliters (mL) to liters (L).
750 mL = 750/1000 = 0.75 L
Step 2: Use the formula for molarity (M) to find the number of moles of CsCl needed.
M = (mol CsCl) / (L of solution)
Rearrange the formula to solve for moles of CsCl:
mol CsCl = M x L of solution
Let's substitute the values:
mol CsCl = 0.100 mol/L x 0.75 L = 0.075 mol
Step 3: Calculate the mass of CsCl using the formula mass and the number of moles obtained.
mass (g) = mol x formula mass
Substitute the values:
mass (g) = 0.075 mol x 168.36 g/mol = 12.627 g
Therefore, 12.627 grams of cesium chloride (CsCl) will be needed to make 750 mL of a 0.100 M CsCl aqueous solution.