What are the zeroes of y = x2 + 2x – 8?
–4, 2
4, –2
–4, –2
4, 2
well, x^2+2x-8 = (x+4)(x-2)
that help?
To find the zeroes of the quadratic equation y = x^2 + 2x - 8, we can set the equation equal to zero and solve for x.
So, we have x^2 + 2x - 8 = 0.
To solve this quadratic equation, we can use factoring, completing the square, or the quadratic formula.
In this case, we can use factoring to find the zeroes.
First, we need to factor the quadratic equation. The factors will be of the form (x + a)(x + b), where a and b are the values that multiply together to give -8 and add up to 2.
The factors of 8 are 1, 2, 4, and 8. We need to find a pair of factors whose sum is 2, which are 4 and -2.
So, we can write the quadratic equation as (x + 4)(x - 2) = 0.
Now, we can set each factor equal to zero and solve for x:
x + 4 = 0 --> x = -4
x - 2 = 0 --> x = 2
Therefore, the zeroes of the quadratic equation y = x^2 + 2x - 8 are -4 and 2.
So, the correct answer is A: -4, 2.