The area of a rectangle increase 5/8 of a square inch as the width increase 1/8 of an inch how many square inches does the area increases if the width increases 1 inch?
width --- x
length ---y
area = xy
new width = x+1/8 = (8x+1)/8
length = y
new area = y(8x+1)/8
y(8x+1)/8 - xy = 5/8
times 8
y(8x+1) - 8xy = 5
8xy + y - 8xy = 5
y = 5
second case:
width = x+1
length = y
area = (x+1)(y)
= xy + y
increase in area = xy+y - xy
= y
= 5
The enlarged rectangle has a new strip of 1/8 inch wide, meaning it is 5 inches long.
If x grows by 1 inch (8 times as much), the area will also grow by 8 times as much, or 5 in^2.
This assumes that y does not change in all the manipulations.
doesn't help at all because it doesn't answer my question in any way
To find out how many square inches the area increases when the width increases by 1 inch, we need to determine the relationship between the width and area of the rectangle.
Let's consider the given information: the area of the rectangle increases by 5/8 of a square inch when the width increases by 1/8 of an inch.
So, for every 1/8 inch increase in width, there is a corresponding increase of 5/8 square inch in the area.
To find out how many square inches the area increases when the width increases by 1 inch, we need to determine the number of 1/8 inch increases within 1 inch.
1 inch can be divided into 8 equal parts, where each part represents a 1/8 inch increase.
Since the area increases by 5/8 square inch for each 1/8 inch increase in width, we can calculate the total area increase for 1 inch by multiplying the number of 1/8 inch increases (8) by the area increase for each 1/8 inch (5/8).
Total area increase = (Number of 1/8 inch increases) * (Area increase for each 1/8 inch)
= 8 * (5/8)
= 5 square inches
Therefore, the area of the rectangle increases by 5 square inches when the width increases by 1 inch.