the current I in an electrical conductor varies inversely as the resistance R of the conductor . the current is 4 amps when the resistance is 280 ohms . what is the current when
the resistance is 40 ohms ?
no clue . someone else please help
I = 280/40 * 4 = 28 Amps.
or
E = I*R = 4*280 = 1120 v.
I = E/R = 1120/40 = 28 Amps.
To solve this problem, we can use the inverse variation formula:
I = k/R
where I is the current, R is the resistance, and k is the constant of variation.
To find the value of k, we can use the given information that the current is 4 amps when the resistance is 280 ohms:
4 = k/280
To solve for k, we can multiply both sides of the equation by 280:
4 * 280 = k
k = 1120
Now that we know k, we can substitute it back into the inverse variation equation:
I = 1120/R
To find the current when the resistance is 40 ohms, we can substitute R with 40:
I = 1120/40
Simplifying the expression:
I = 28 amps
Therefore, the current when the resistance is 40 ohms is 28 amps.