A mass of 4kg rest on a rough table with coefficient of force 0.4. Find tje force sufficient to move it horizontally.

normal force = m g = 4*9.81

friction force = .4 * 4 * 9.81 = answer in Newtons

If a force of 10N is neede to move a mass of 2kg resting on a table fine the coefficient of friction. ( take 9.8m/s). Gravity

To find the force required to move the 4kg mass horizontally on the rough table, you can use the equation:

Force of Friction = Coefficient of Friction * Normal Force

The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, since the mass is at rest on the table, the normal force is equal to the weight of the object, which is given by:

Weight = mass * gravitational acceleration

Assuming the gravitational acceleration is approximately 9.8 m/s², we can calculate the weight of the 4kg mass:

Weight = 4kg * 9.8 m/s² = 39.2 N

Substituting the coefficient of friction (0.4) and the normal force (39.2 N) into the equation, we can calculate the force of friction:

Force of Friction = 0.4 * 39.2 N = 15.68 N

Therefore, the force required to move the 4kg mass horizontally on the rough table is approximately 15.68 Newtons.

To find the force required to move the mass horizontally, we need to calculate the maximum static friction acting on the mass.

The formula for static friction is:

Fs = μs * N

where Fs is the maximum static friction, μs is the coefficient of friction, and N is the normal force.

In this case, the normal force is equal to the weight of the mass, since it is resting on a horizontal table. The formula for weight is:

N = mg

where m is the mass and g is the acceleration due to gravity (approximately 9.8 m/s^2).

Substituting these values into the formula for static friction, we get:

Fs = μs * mg

Given that the mass is 4 kg and the coefficient of friction is 0.4, we can calculate the force required to move the mass horizontally.

Fs = (0.4)(4 kg)(9.8 m/s^2)
Fs = 15.68 N

Therefore, a force of approximately 15.68 Newtons would be sufficient to move the 4 kg mass horizontally.