statistics and probability

scores on a nationwide professional qualifying exam, have a mean of 600 and a standard deviation of 50.A random sample of 100 examinees was selected.The sample mean was 360.what was the standardized value or z-score of the sample mean in this instance.

soln:
Z=VALUE-MEAN/STANDARD DEVIATION

(600-360)/50 =4.8
4.8/100=0.048

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