Five consecutive whole numbers has s sum of 225.what is the largest number
Ah, the elusive sum of five consecutive whole numbers! Let's see if we can unravel this math mystery with a hint of humor.
Now, to find the largest number, we need to divide the sum evenly among the five numbers. So, let's call the first number "x."
The next four numbers would then be x + 1, x + 2, x + 3, and x + 4.
Adding all these numbers up, we have:
x + (x + 1) + (x + 2) + (x + 3) + (x + 4) = 225.
Now, let's just solve this equation and find our answer.
x + x + 1 + x + 2 + x + 3 + x + 4 = 225
5x + 10 = 225
5x = 215
Now, let's divide both sides by 5 to find x:
x = 43
So, the largest number in the consecutive sequence would be x + 4, which is 43 + 4, equaling 47.
Therefore, the largest number in the sequence is 47. Voila!
Let's solve this step by step.
Step 1: Let's assume the first number is x.
Step 2: The next four consecutive numbers would be (x+1), (x+2), (x+3), and (x+4).
Step 3: According to the question, the sum of these five numbers is 225.
So, x + (x+1) + (x+2) + (x+3) + (x+4) = 225.
Step 4: Now, let's simplify the equation.
5x + 10 = 225
Step 5: Subtract 10 from both sides of the equation.
5x = 215
Step 6: Divide both sides of the equation by 5.
x = 43
Therefore, the largest number among the five consecutive whole numbers is x + 4.
43 + 4 = 47.
So, the largest number is 47.
To find the largest number among five consecutive whole numbers, we first need to find the first number in the sequence.
Let's assume the first number is x.
The next four consecutive whole numbers would be x + 1, x + 2, x + 3, and x + 4.
To find the sum of these five consecutive whole numbers, we can add them up:
x + (x + 1) + (x + 2) + (x + 3) + (x + 4) = 225
Simplifying the expression:
5x + 10 = 225
Subtracting 10 from both sides:
5x = 215
Dividing both sides by 5:
x = 43
So, the first number in the sequence is 43.
The largest number would then be x + 4:
43 + 4 = 47
Therefore, the largest number among five consecutive whole numbers that have a sum of 225 is 47.
let x-first no.
x+(x+1)+(x+2)+(x+3)+(x+4)=225
5x+10=225
x=43
largest no.= (x+4)=43+4= 47
Ans: 47