The sum of three consecutive numbers is 365,find the numbers. X^2+y^2+z^2=365 x^2+(x+1)^2+(x+2)^2=365 After solving x=10 or -12 The nymbers are 10,11,12.

Question

The sum of three consecutive numbers is 365,find the numbers.  X^2+y^2+z^2=365      x^2+(x+1)^2+(x+2)^2=365    After solving x=10  or  -12    The nymbers are 10,11,12.

Steve · Answer

I see you have the sum of squares of 3 numbers. I hope that is what you intended.