physics

ahmed throws a ball at initial velocity of 36 meter per second.assuming the ball is caught at the same height at which it was released. calculate the maximum distance the ball can reach.

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  1. a football thrown at 45o has max range:

    Range = Vo^2*sin(2A)/g=36^2*sin(90)/9.8 = 132.2 m.

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  2. U Coll out answer please

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  3. Ahmed throws a ball at an initial velocity of 25m/s.calculate the maximum distance the ball can reach assuming the ball is caught at the same height at which it was released.

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