How do i prepare 17% HNO3 from 69%-70.5% HNO3 of 1.42g/ml density
To prepare a 17% HNO3 solution, you need to dilute the concentrated solution (69%-70.5% HNO3) with water. The process involves calculating the amount of concentrated solution and the volume of water needed.
Here are the steps to prepare the 17% HNO3 solution:
Step 1: Determine the concentration of the concentrated solution.
- The given concentrated solution is 69%-70.5% HNO3. Let's use the average value, which is 69.75% (midway between the given range).
Step 2: Calculate the desired concentration of the final solution.
- The desired concentration is 17% HNO3.
Step 3: Determine the volume of the concentrated solution needed.
- Let's assume you want to prepare 100 mL of the final solution.
- For a 17% HNO3 solution, the volume of HNO3 can be calculated as:
Volume of HNO3 = (Desired concentration / Concentration of concentrated solution) x Volume of final solution
Volume of HNO3 = (17 / 69.75) x 100 mL
Step 4: Calculate the volume of water needed.
- To prepare the final solution, the volume of water can be calculated as:
Volume of water = Volume of final solution - Volume of HNO3
Step 5: Calculate the mass of the concentrated solution needed.
- Use the density of the concentrated solution (1.42 g/mL) to calculate the mass required as:
Mass of concentrated solution = Volume of concentrated solution x Density of concentrated solution
To summarize, calculating the amount of each component needed:
- Volume of HNO3 = (17 / 69.75) x 100 mL
- Volume of water = Volume of final solution - Volume of HNO3
- Mass of concentrated solution = Volume of concentrated solution x Density of concentrated solution
Once you have these values, you can measure the appropriate volumes of the concentrated solution and water, then mix them together to prepare the desired 17% HNO3 solution.