# math

the sum of two numbers exceeds their product by one. their differences is equal to their product less five . find the two numbers

1. 👍 2
2. 👎 1
3. 👁 1,451
1. let n-1st no.
m-2nd no.
n+m=(nXm)+1-----eqtn. 1
n-m=(nXm)-5-----eqtn. 2

solve by elimination

n+m=(nXm)+1-----eqtn. 1
-
n-m=(nXm)-5-----eqtn. 2
________________________________
2m=6

m=3
subst. to eqtn 1 or 2

n+m=(nXm)+1-----eqtn. 1
n+3=3n+1
-2n=-2
n=1

therefore, the nos. are 3 and 1

1. 👍 5
2. 👎 1
2. True and thank you for the answer

1. 👍 2
2. 👎 0
3. Thanks

1. 👍 1
2. 👎 0
4. true and thanks for the answer

1. 👍 1
2. 👎 0
5. Right

1. 👍 1
2. 👎 0
6. Not true thanks

1. 👍 1
2. 👎 0
7. correct

1. 👍 1
2. 👎 0

1. 👍 1
2. 👎 0

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