math

the sum of two numbers exceeds their product by one. their differences is equal to their product less five . find the two numbers

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  2. 👎 1
  3. 👁 1,451
  1. let n-1st no.
    m-2nd no.
    n+m=(nXm)+1-----eqtn. 1
    n-m=(nXm)-5-----eqtn. 2

    solve by elimination

    n+m=(nXm)+1-----eqtn. 1
    -
    n-m=(nXm)-5-----eqtn. 2
    ________________________________
    2m=6

    m=3
    subst. to eqtn 1 or 2

    n+m=(nXm)+1-----eqtn. 1
    n+3=3n+1
    -2n=-2
    n=1

    therefore, the nos. are 3 and 1

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  2. True and thank you for the answer

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  3. Thanks

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  4. true and thanks for the answer

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  5. Right

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  6. Not true thanks

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  7. correct

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  8. i don't understand please help me

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