the sum of two numbers exceeds their product by one. their differences is equal to their product less five . find the two numbers
let n-1st no.
m-2nd no.
n+m=(nXm)+1-----eqtn. 1
n-m=(nXm)-5-----eqtn. 2
solve by elimination
n+m=(nXm)+1-----eqtn. 1
-
n-m=(nXm)-5-----eqtn. 2
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2m=6
m=3
subst. to eqtn 1 or 2
n+m=(nXm)+1-----eqtn. 1
n+3=3n+1
-2n=-2
n=1
therefore, the nos. are 3 and 1