prealgebra

The length of a rectangle is 3 more than it's width. the perimeter of the rectangle is 58cm. what are the rectangle dimensions?

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  1. P = 2L + 2W

    58 = 2(W + 3) + 2W

    Solve for W.

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    Ms. Sue
  2. w and w+3

    perimeter = 2 w + 2 (w +3) = 58

    4 w + 6 = 58

    4 w = 52

    w = 13

    so 13 by 16

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