Algebra

The Browns installed 58 feet of fencing around a rectangular play yard. If the yard covers 204 square feet, what are its dimensions?

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  1. 204 = 17*12
    2(17+12) = 58

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  2. 2 L + 2 w = 58
    so L + w = 29
    and L=29-w

    w (29-w) = 204

    29 w - w^2 = 204

    w^2 - 29 w + 204 = 0

    w = [ 29 +/- sqrt(841-816) ] / 2

    w = [ 29 +/- 5 ]/2

    w = 34/2 = 17
    L = 12 that works
    or
    L =17 and w = 12

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