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A person who is 1.1 m tall throws a ball with a speed of 5.2 m/s at an angle of 56 degrees above the horizontal. What are the x and y components of the velocity (in m/s) of the ball the instant before it strikes the ground? The acceleration due to gravity is 10 m/s2

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Kevin

  1. Vo = 5.2m/s[56o].
    Xo = 5.2*Cos56 = 2.91 m/s.
    Yo = 5.2*sin56 = 4.31 m/s.

    h=-Yo^2/2g + 1.1=-(4.31)^2/-20 + 1.1
    = 2.03 m. Above gnd.

    Y^2 = Yo^2 + 2g*h = 0 + 20*2.03 = 40.6
    Y = 6.37 m/s.

    X = Xo = 2.91 m/s.

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    Henry

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