On a certain farm, on average, 64 hens lay 768 eggs in 64 days. On that same farm, on average, 46 hens eat 46 kilograms of wheat in 46 days. On this farm, on average, the consumption of how much wheat (in kg) corresponds to 2 dozen eggs?
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To find out the consumption of wheat corresponding to 2 dozen eggs, we need to determine the average consumption of wheat per egg.
First, let's calculate the average number of eggs laid by each hen per day. We can do this by dividing the total number of eggs laid (768) by the number of days (64) and the number of hens (64):
Average eggs per hen per day = (768 eggs) / (64 days) = 12 eggs per day/hen.
Next, we can calculate the average eggs per hen per day corresponding to 2 dozen eggs:
2 dozen eggs = 2 x 12 = 24 eggs.
Now, we need to find out how many hens are required to lay 24 eggs per day. To do this, we divide the average eggs per hen per day corresponding to 2 dozen eggs by the average eggs per hen per day:
Number of hens for 24 eggs = (24 eggs) / (12 eggs per day/hen) = 2 hens.
Finally, we need to determine the average wheat consumption per hen per day. We can do this by dividing the total wheat consumption (46 kg) by the number of days (46) and the number of hens (46):
Average wheat consumption per hen per day = (46 kg) / (46 days) = 1 kg per day/hen.
To find the wheat consumption corresponding to 2 dozen eggs, we multiply the average wheat consumption per hen per day by the number of hens (2):
Wheat consumption for 2 dozen eggs = (1 kg per day/hen) x (2 hens) = 2 kg.
Therefore, the consumption of wheat corresponding to 2 dozen eggs is 2 kilograms.