1.in this problem, you will draw three rays for each triangle. each ray starts at a vertex and passes through the interior of the triangle.(how many triangles am i drawing)
what is the maximum number of points of intersection between the rays?
To find the maximum number of points of intersection between the rays, we need to determine the number of possible intersections for each pair of rays.
In this problem, you will be drawing three rays for each triangle. Let's number the rays as Ray1, Ray2, and Ray3.
For Ray1, it can intersect with Ray2 and Ray3, so it has the potential to create 2 intersections.
For Ray2, it can also intersect with Ray1 and Ray3, resulting in another 2 intersections.
Similarly, Ray3 can intersect with Ray1 and Ray2, creating 2 intersections.
To find the total number of possible intersections, we add the possible intersections for each pair of rays:
Total intersections = intersections between Ray1 and Ray2 + intersections between Ray1 and Ray3 + intersections between Ray2 and Ray3
= 2 + 2 + 2
= 6
Therefore, the maximum number of points of intersection between the rays is 6.
In conclusion, you will be drawing three rays for each triangle, and the maximum number of points of intersection between the rays is 6.