In a right triangle normal is 40cm,hypotenuse is 44.Find the value of base?
An aerial 20 meter tail is to be supported by 2 guy wires each 70 meter from its base.How long will each guy wire be?
b^2 = 44^2-40^2
same for the other problem. Remember that if the two legs are a and b, and the hypotenuse is c,
a^2 + b^2 = c^2
To find the value of the base in a right triangle, we can use the Pythagorean theorem, which states that in a right triangle, the sum of the squares of the lengths of the two legs is equal to the square of the length of the hypotenuse.
In this case, we are given the length of the normal (one of the legs) as 40 cm, and the length of the hypotenuse as 44 cm. Let's use the Pythagorean theorem to solve for the length of the base.
The Pythagorean theorem can be written as:
base^2 + normal^2 = hypotenuse^2
Let's substitute the given values into the equation:
base^2 + 40^2 = 44^2
Simplifying the equation:
base^2 + (40 * 40) = (44 * 44)
base^2 + 1600 = 1936
Subtracting 1600 from both sides:
base^2 = 336
To solve for the value of the base, we need to take the square root of both sides of the equation:
√(base^2) = √(336)
base = √(336)
Evaluating the square root:
base ≈ 18.33 cm
Therefore, the value of the base in the right triangle is approximately 18.33 cm.